If 1 kg of water (1L) is heated from 0 C to its boiling point at a pressure of 101.3 kPa, how much latent heat is required?

To determine the amount of latent heat required for 1 kg of water to change from liquid to vapor at its boiling point, it's essential to understand the concept of latent heat of vaporization. When water reaches its boiling point at 101.3 kPa (standard atmospheric pressure), it requires a specific amount of energy to convert from a liquid state to a gaseous state without changing its temperature.

The latent heat of vaporization for water is approximately 2257 kJ per kilogram. This means that for each kilogram of water, 2257 kJ of energy must be added to facilitate the phase change from liquid to vapor at the boiling point.

In this scenario, since we are heating 1 kg of water from 0 °C to its boiling point and then allowing it to vaporize, the amount of latent heat needed for the vaporization portion of the process is 2257 kJ. The other options provided do not correspond to the known value for the latent heat of vaporization for water at standard conditions, making the correct choice the one that aligns with the recognized physical properties of water.